(x^2+2x-5)(x+4)=

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Solution for (x^2+2x-5)(x+4)= equation: 


Simplifying
(x2 + 2x + -5)(x + 4) = 0

Reorder the terms:
(-5 + 2x + x2)(x + 4) = 0

Reorder the terms:
(-5 + 2x + x2)(4 + x) = 0

Multiply (-5 + 2x + x2) * (4 + x)
(-5(4 + x) + 2x * (4 + x) + x2(4 + x)) = 0
((4 * -5 + x * -5) + 2x * (4 + x) + x2(4 + x)) = 0
((-20 + -5x) + 2x * (4 + x) + x2(4 + x)) = 0
(-20 + -5x + (4 * 2x + x * 2x) + x2(4 + x)) = 0
(-20 + -5x + (8x + 2x2) + x2(4 + x)) = 0
(-20 + -5x + 8x + 2x2 + (4 * x2 + x * x2)) = 0
(-20 + -5x + 8x + 2x2 + (4x2 + x3)) = 0

Combine like terms: -5x + 8x = 3x
(-20 + 3x + 2x2 + 4x2 + x3) = 0

Combine like terms: 2x2 + 4x2 = 6x2
(-20 + 3x + 6x2 + x3) = 0

Solving
-20 + 3x + 6x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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